0
1.7kviews
An Aero-plane travels in air of pressure of 1 bar at 10 degree celsuis at a speed of 1800 km/hr. Find the Mach number and Mach angle. Take k=1.4 and R=287 J/Kg K.

What is k=1.4?

1 Answer
1
243views


Given,

Pressure = 1 bar

Speed (V) = 1800 km / hr = 500 m/s

K = 1.4

R = 287 J/kg K

Temperature (t) = 10˚ C

T = 10 + 273 = 283 k



As we know, the velocity of sound is (adiabatic process) -

$C = \sqrt{KRT} = \sqrt{1.4 \times 287 \times 283}$

$C = 337.20\ m/s.$


$\therefore\ Mach\ Number\ = \frac{v}{c} = \frac{500}{337.20} = 1.48$

$Also,\ Mach\ angle\ is,\ Sin \alpha \frac{c}{v} = \frac{1}{m}$

$\therefore \alpha = sin^{-1} (\frac{1}{1.48})$

$Mach\ angle\ is\ \alpha = 42.40˚$


So, finally Mach number is 1.48 and Mach Angle is 42.40.

1

Can you please improve the Tag for this question


Please log in to add an answer.