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Calculate the shear stress at the neutral axis in a beam of triangular section with a base of 40 mm and height 20 mm, subjected to a shear force of 3 kN.

written 3.3 years ago by bhoral455 • 20

modified 3.0 years ago by Chandan15 • 300

strength of materials

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written 3.0 years ago by Chandan15 • 300

•   modified 3.0 years ago

Shear Stress at Neutral Axis in case of triangle

$\tau_{N A}$ (triangle) $=\frac{4}{3}$ ×τavg $=\frac{4}{3} \times \frac{2 V}{D h}$ $V=3 \mathrm{KN}, b=40 \mathrm{~mm}, h=20 \mathrm{~mm}$ $τ_{N A}=\frac{4}{3} \times \frac{2 \times 3 \times 103}{40 \times 20}=10 \mathrm{~N} / \mathrm{mm}^{2}$

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