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Prepare rate analysis for Ist class brick work in superstructure in CM (1:4)
1 Answer
written 8.4 years ago by |
Assume 10 cu m of brickwork
1 cu m = 500 no. of bricks
10 cu m= 5000 no of bricks
Volume of one brick $= 0.19 × 0.09 ×0.09 =1.539 ×10^{-3}$
Total volume $= 5000×1.539×10^{-3}=7.695 cu m$
Dry volume of mortar $= 10-7.695 = 2.305cu m$
Wastage $= 1.2 {\times} 2.996 = 3.596 cu m$
Cement $= \dfrac{3.596}{1+4}=0.7192$
No of cement bags $= \dfrac{07192}{0.035}=20.54 ≈21 bags$
Sand $= 0.7192 {\times} 4 = 2.87 cu m$
Final Cost = Rs. 5640/ cu m