Mumbai University > CIVIL > Sem 7 > Quantity survey Estimation and valuation

Marks: 10 M

Year: May 2014

1. P.C.C (1:5:10) in foundation bed

   Consider first 10 cu m

   Wet volume $= 30 \ \% \ extra \\ = 1.3 {\times} 10 = 13 m^3$

   Wastage $= 20 % extra \\ \; = 1.2 {\times} 13 = 15.6 m^3$

   Cement $= \dfrac{15.6}{\sum{proportion}}= \dfrac{15.6}{1+5+10}=0.975$

   No of cement bags $= \dfrac{0.975}{0.035}=27.85 ≈28 \ bags$

   Sand $= 0.975 {\times} 5= 4.875 \ cu \ m$

   Stone ballast $= 10 {\times} 0.975 = 9.75 \ cu \ m$

   Rates( Assumed)

   Cement bag $= Rs 330 / bag$

   Sand = $Rs. 2120 /m^3$

   Stone ballast $= Rs. 880 /m^3$

Final Cost = 3870.4/cu m

1. Ist class burnt brick masonary in superstructure in C.M 1:3

   Assume 10 cu m of brickwork

   1 cum = 500 No. of brick

   10 cum = 5000 No of brick

   Volume of one brick $= 0.19 × 0.09 ×0.09 =1.539 ×10^{-3}$

   Total volume $= 5000×1.539×10^{-3}=7.695 \ cu \ m$

   Dry volume of mortar $= 10-7.695 = 2.305 \ cu \ m$

   Wet volume $= 1.3 {\times} 2.305 = 2.996$

   Wastage $= 1.2 {\times} 2.996 = 3.596 cu m$

   Cement $= \frac{3.596}{1+3}=0.899$

   No of cement bags $= \frac{0.899}{0.035}=25.69≈26 bags$

   Sand $= 0.899 {\times} 3 = 2.697 \ cu \ m$

Final Cost = 57896 cu m