Mumbai University > CIVIL > Sem 7 > Quantity survey Estimation and valuation

Marks: 14 M

Year: May 2013

1. Ist class brick masonry in C.M. (1:4)

   Assume 10 cu m of brickwork

   1 cu m = 500 no. of bricks

   10 cu m= 5000 no of bricks

   Volume of one brick $= 0.19 × 0.09 ×0.09 =1.539 ×10^{-3}$

   Total volume $= 5000×1.539×10^{-3}=7.695 \ cu \ m$

   Dry volume of mortar $= 10-7.695 = 2.305 \ cu \ m$

   Wastage $= 1.2 {\times} 2.996 = 3.596 \ cu \ m$

   Cement $= \frac{3.596}{1+4}=0.7192$

   No of cement bags $= \frac{0.7192}{0.035}=20.54 ≈21 bags$

   Sand $= 0.7192 {\times} 4 = 2.87 \ cu \ m$

Final cost = Rs. 5640/ cu m

1. R.C.C work for column (1:1.5:3) with 1% steel

   Consider first 10 cu m

   Wet volume $= 30 \% \ extra \\ \ = 1.3 x 10 = 13 (m^3)$

   Wastage $= 20 \% \ extra \\ \; =1.2 x 13 = 15.6(m^3)$

   Cement $= \frac{15.6}{\sum {proportion}}= \frac{15.6}{1+3+6}= \frac{15.6}{10}=1.56 ≈1.56 (m^3)$

   $1 bag = 50 kg =35 litres = 0.035 (m^3)$

   No of cement bags $= 1.56/0.035 =44.57 ≈45 \ \ bags$

   $Sand = 3 {\times} 1.56 = 4.68(m^3)$

   $Stone \ \ ballast = 6 {\times} 1.56 = 9.36 (m^3)$

   Rates (Assumed)

   $cement \ \ bag = Rs. 330/bag \\ Sand = Rs. 2120/ (m^3) \\ Stone \ \ ballast = Rs. 880 / (m^3)$

Final Cost/cum = Rs. 4437