Mumbai University > CIVIL > Sem 7 > Quantity survey Estimation and valuation

Marks: 6 M

Year: Dec 2013

Assume 10 cu m of brickwork

1 cu m = 500 no of brick

10 cu m = 5000 no of brick

X volume of one brick $= 20 {\times} 10 {\times} 10 (mm) \\ \; = 2 {\times} 10^{-3} cu m$

Total volume bricks $= 5000 ×2{\times}10^{-3}=10 \ cu \ m$

Volume of one brick $= 0.19×0.09×0.09=1.539{\times}10^{-3}=7.695 \ cu \ m$

Dry Volume of mortar $= 10-7.695 = 2.305 \ cu \ m$

Wet volume $= 1.3 {\times} 2.305 = 2.996 \ cu \ m$

Wastage $= 1.2 {\times} 2.996 = 3.596 \ cu \ m$

Cement $= \frac{3.596}{1+6}=0.514$

No of cement bags $= \frac{0.514}{0.035}=14.67 ≈15 bags$

Sand $= 0.514 {\times} 6 =3.084 \ cu \ m$

Final Cost = 5461.9/cu m