Mumbai University > CIVIL > Sem 7 > Quantity survey Estimation and valuation

Marks: 12 M

Year: May 2012

1. P.C.C. (1:3:6) in foundation bed

   Consider first 10 cu m

   Wet volume $= 30 \% \ extra \\ \ = 1.3 x 10 = 13 (m^3)$

   Wastage $= 20 \% \ extra \\ \; =1.2 x 13 = 15.6(m^3)$

   Cement $= \frac{15.6}{\sum {proportion}}= \frac{15.6}{1+3+6}= \frac{15.6}{10}=1.56 ≈1.56 (m^3)$

   $1 bag = 50 kg =35 litres = 0.035 (m^3)$

   No of cement bags $= 1.56/0.035 =44.57 ≈45 \ \ bags$

   $Sand = 3 {\times} 1.56 = 4.68(m^3)$

   $Stone \ \ ballast = 6 {\times} 1.56 = 9.36 (m^3)$

   Rates (Assumed)

   $cement \ \ bag = Rs. 330/bag \\ Sand = Rs. 2120/ (m^3) \\ Stone \ \ ballast = Rs. 880 / (m^3)$

Final Cost/cum = Rs. 4437

1. Internal plaster in CM (1:5)

   Assume 100 sq m of plaster surface Dry volume $= 100 {\times} 0.012 = 1.2 cu m$ (fix values if thk not given)

   Wet volume $= 30 \% \ extra \\ \; =1.3 {\times} 1.2 \\ \; =1.56 cu m$

   Cement $= \frac{1.872}{\sum{proportion}} =\frac{1.872}{1+5}=\frac{1.872}{6} =0.312 \ cu \ m$

   No of cement bags $= \frac{0.312}{0.035} =8.91 {\times} 9 \ \ bags$

$\hspace{0.5cm}$ a) Sand $= 0.312{\times}5=1.56 \ cu \ m$

Final Cost/ Sq m = Rs 200.53