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To reduce co-channel interference, co-channel cell must be separated by a minimum distance.
When the size of the cell is approximately the same
– co-channel interference is independent of the transmitted power
– co-channel interference is a function of
- R: Radius of the cell
- D: distance to the center of the nearest co-channel cell
Increasing the ratio Q=D/R, the interference is reduced.Where Q is called the co-channel reuse ratio
For a hexagonal geometry
$Q=\dfrac{D}{R}=\sqrt{3N}$
A small value of Q provides large capacity. A large value of Q improves the transmission quality - smaller level of co-channel interference
- A tradeoff must be made between these two objectives
Cluster Size | Co-channel Reuse Ratio (Q) | |
---|---|---|
$i=1,\ j=1$ | 3 | 3 |
$i=1,\ j=2$ | 7 | 4.58 |
$i=2,\ j=2$ | 12 | 6 |
$i=1,\ j=3$ | 13 | 6.34 |
Table- Co-channel Reuse Ratio for Some Values of N
- Let i0 be the number of co-channel interfering cells. The signal-to-interference ratio (SIR) for a mobile receiver can be expressed as
$\dfrac{S}{I}=\dfrac{S}{\sum^{i_o}_{i=1}}$
S: the desired signal power
Ii : interference power caused by the ith interfering co-channel cell base station
- The average received power at a distance d from the transmitting antenna is approximated by
$P_r=P_o\left(\dfrac{d}{d_o}\right)^{-n}$
Where n is path loss exponent which range between 2 and 4.
- When the transmission power of each base station is equal, SIR for a mobile can be approximated as
$\dfrac{S}{I}=\dfrac{R^{-n}}{\sum^{i_o}_{i=1}(D_i)^{-n}}$
Then the relationship between S/I and N will $\dfrac{S}{I}=\dfrac{\left(\dfrac{D}{R}\right)^n}{i_n}=\dfrac{(\sqrt{3N})^n}{i_n}$