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Implement the given function using 8:1 Multiplexer F(A, B, C, D)=∑(0,1,4,5,6,8,10,12,13).
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The total number of inputs are 4. So the number of outcomes are 24=16.

But, we have a 8:1 mux. So, we use the following table -

D7 D6 D5 D4 D3 D2 D1 D0
A 0 1 2 3 4 5 6 7
à 8 9 10 11 12 13 14 15

The bits from D0 to D0 have been alloted with the outputs possible from 4 inputs.

Now, the outcomes that have been specified to obtain the function will be set to 1.

The output for the combination would be -

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