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State and Prove DeMorgan's Laws.
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written 3.9 years ago by |
DeMorgan's Theorems:-
Theorem 1:-
¯AB=¯A+¯B
Proof:-
A | B | ¯AB | ¯A | ¯B | ¯A+¯B |
---|---|---|---|---|---|
0 | 0 | 1 | 1 | 1 | 1 |
0 | 1 | 1 | 1 | 0 | 1 |
1 | 0 | 1 | 0 | 1 | 1 |
1 | 1 | 0 | 0 | 0 | 0 |
Theorem 2:-
¯A+B=¯A ¯B
The circuit representation is given below
Proof:-
A | B | ¯A+B | ¯A | ¯B | ¯A ¯B |
---|---|---|---|---|---|
0 | 0 | 1 | 1 | 1 | 1 |
0 | 1 | 0 | 1 | 0 | 0 |
1 | 0 | 0 | 0 | 1 | 0 |
1 | 1 | 0 | 0 | 0 | 0 |