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find initial value of, f(t)= 20-10t-e-25t verify using initial value theorem.
1 Answer
written 3.9 years ago by |
limt→0 f(t)=limt→∞[20−10t−e−25t]=20−1=19
f(t)=20−10t−e−25t
Taking Laplace transform
f(s)=20s−10s2−1s+25s(f)=20−10s−ss+25
By initial value theorem
lims→∞ f(t)=lims→∞[20−10s−ss+25]=20−1=19