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Realise the following function in Cauer-I and Cauer-II from
Z(s)=(s+1)(s+3)(s+2)(s+6)
1 Answer
written 3.9 years ago by |
$\begin{align} z\left(s\right)&=\dfrac{\left(s+1\right)\left(s+3\right)}{\left(s+2\right)\left(s+6\right)}\[2ex] &=\frac{s^2+4s+3}{s^2+8s+12} \end{align}$
AUER –I
As negative terms result continued frailer expansion of y(s) is carried out
Cauer -11