Answer:  Applying KVL to mesh 1 , 

  $V_1=3I_1+2I_2-I_3$.......................(1)

Applying KVL to mesh 2 ,

$V_2=2I_1+6I_2+4I_3$......................(2)

Applying KVL to mesh 3 , 

$13I_3-I_1+4I_2=0$

$\therefore I_3=\dfrac{1}{13}I_1-\dfrac{4}{13}I_2$......................(3)

Substituting the equation (3) in (1),

$V_1=3I_1+2I_2-\dfrac{1}{3}I_1+\dfrac{4}{13}I_2$

$\therefore V_1=\dfrac{38}{13}I_1+\dfrac{30}{13}I_2$......................(4)

Substituting the equation (3) in (2),

$V_2=2I_1+6I_2+4(\dfrac{1}{13}I_1-\dfrac{4}{13}I_2)$

$\therefore V_2=\dfrac{30}{13}I_1+\dfrac{62}{13}I_2$.......................(5)

 The T network consists of three impedances . …