The current I(S) in network is given by \[ I(S) = \dfrac {2(S)} {(S+1)(S+2)}. \] Plot the pole-zero pattern in the S-plane and hence obtain i(t).

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The current I(S) in network is given by

$I(S) = \dfrac {2(S)} {(S+1)(S+2)}.$ Plot the pole-zero pattern in the S-plane and hence obtain i(t).

written 3.9 years ago by

teamques10 ★ 69k

modified 3.1 years ago by

pedsangini276 • 4.8k

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written 3.9 years ago by

teamques10 ★ 69k

Given $I(s)=\dfrac{2s}{(s+1)(s+2)}$

To get poles,equate denominator of I(s) to zero

(s+1)(s+2)=0

poles are s1= -1 and s2 = -2

To get zero, equate numerator of I(s) to zero.

2s=0

zero is s=0

Pole - zero plot

To obtain i(t), need to apply inverse laplase to I(s)

Now Apply Inverse Laplace …

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