$200\times10^3I_B+V_{BE}+2\times10^{-3}I_B=20\ \rightarrow200\times10^3I_B+2\times10^3(90+1)I_B=20-0.7\ \rightarrow382\times10^3I_B=19.3\ \rightarrow I_B=0.05mA\ I_C=\beta I_B=4.54mA\ I_E=(\beta+1)I_B=4.598mA$ We have, $V_0+20=I_E\times2\times10^3=9.195\ V_0=-10.805V\ And \ V_E=V_0=-10.805\ V_{CE}=-V_E=10.805V\ V_B=I_B \ 200\times10^3=10.105V$ We know $S_{ICO}=\dfrac{1+\beta}{1+\beta\left(\dfrac{R_E}{R_B+R_E}\right)}=\dfrac{91}{1.89}=48.12$