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The JFET shown in figure 3b has parameter IDSS=8mA and Vp=4V. Determine VG, IDSQ, VGSQ and VDSQ
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teamques10
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- The Drain Source Voltage of a JFET is given by the equation
VDSQ=VDD−ID(RD+RS)=5−(5×10−3)(3+0.5)×103=−12.5V
- For a Voltage Divider JFET the Voltage between Source and Gate is given as
VGS=−IDRS=−8V
- By Voltage Division we have the Voltage between Gate and Ground as
VGQ=R2VDDR1+R2=1200200×103=6mV
- The Drain Current is given by
$I{D_Q}=\dfrac …
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