By voltage division formula we have

$V_{TH}=V_{CC}\dfrac{R_2}{R_1+R_2}=\dfrac{240}{55}=4.363V$

By volatge division formula we have

$R_{TH}=\dfrac{R_1R_2}{R_1+R_2}=\dfrac{700}{55}=12.72\Omega$

The Base Current is given by the equation

$I_{{B}_Q}=\dfrac{V_{TH}-V_{BE}}{R_{TH}+(\beta+1)R_E}=\dfrac{4.363-0.7}{50500}=7.2\mu A$

We know that the Collector current is product of current gain and base current

$I_{{C}_Q}=\beta I_{{B}_Q}=7.2mA$

By applying KVL  at Collector Emitter Junction we have

$V_{{CE}_Q}=V_{CC}-I_CR_C-I_ER_E=12-5.76-0.0072=6.2328V$