0
434views
Find resistance for the circuit shown to obtain VCE=5V and IC=2mA
1 Answer
0
1views

Applying KVL to the Base - Emitter Loop

VCIBRBVBE=0

where, IB=ICβ

VCICβRBVBE=0

VCVBE=ICβRB

RB=VCVBEICβ

RB=(VCVBE)×βIC

RB=(100.7)×1002×103

RB=465 KΩ__

Applying KVL to the Collector - Emitter Loop

VCICRCVCE=0

VCVCE=ICRC

RC=VCVCEIC

RC=1052×103

RC=2.5 KΩ__

Please log in to add an answer.