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Find resistance for the circuit shown to obtain VCE=5V and IC=2mA
1 Answer
written 3.9 years ago by |
Applying KVL to the Base - Emitter Loop
VC−IBRB−VBE=0
where, IB=ICβ
VC−ICβRB−VBE=0
VC−VBE=ICβRB
RB=VC−VBEICβ
RB=(VC−VBE)×βIC
RB=(10−0.7)×1002×10−3
∴RB=465 KΩ__
Applying KVL to the Collector - Emitter Loop
VC−ICRC−VCE=0
VC−VCE=ICRC
RC=VC−VCEIC
RC=10−52×10−3
∴RC=2.5 KΩ__