• We know that the Thevenins Voltage is given by

$V_{th}=V_{cc}\dfrac{R_2}{R_1+R_2}=20\dfrac{370}{70}=105.71V$

• Since R1 and R2 are in parallel we have

$R_{th}=\dfrac{R_1R_2}{R_1+R_2}=\dfrac{21000}{370}=56.756\Omega$

• For the purpose of bias stabilisation we have the Collector Current given by the equation

$I_{{c}_Q}=\beta I_b$

• The base current is given by th equation

$I_b=\dfrac{V_{th}-V_{BE}}{{R_{th}+(\beta+1)R_E}}=\dfrac{{108.7}-{0.7}}{{{56.756}+505000}}=\dfrac{108}{505056.756}=2.13mA$

• Hence the collector current is

$I_{{c}_{Q}}=\beta I_b=2.13A$

• By applying KVL at the Collecotr Emitter Junction we have

$V_{CE}=V_{CC}-I_CR_C-I_ER_E=20-10.65+10.66=20-0.01=19.99V$