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Determine IDQ, VGSQ VD & VS for the network given below:
1 Answer
written 3.9 years ago by |
VGS=−IDRS ∵ID=IDSS2=4mA VGS=−4×10−3×1.5×103=−6V IDQ=2.6mA VDS=VDD−ID(RS+RD)=16−(2.6×10−3)(3.9×103)=16−10.14=5.86V VS=IDRS=2.6×10−3×1.5×103=3.9V VG=0 VD=VDD+VS=16+3.9=19.9V