0

513views

A ball is dropped from a height of 12m upon a horizontal slab. If it rebounds to height of 4m, find the co-efficient of restitution.

written 3.5 years ago by teamques10 ★ 68k

modified 2.7 years ago by pedsangini276 • 4.8k

engineering mechanics

ADD COMMENT FOLLOW SHARE EDIT

1 Answer

0

34views

written 3.5 years ago by teamques10 ★ 68k

As ball is dropped from 12 m,

$Initial\ velocity\ before\ impact\ = \sqrt{2gh}=\sqrt{2g\times12} \ \ m/s$

As it rebounds to a height of 4m,

$Velocity\ after\ impact\ = \sqrt{2gh}=\sqrt{2g\times4} \ \ m/s$

$\displaystyle \therefore{}e=\dfrac{\sqrt{2g\times{}4}}{\sqrt{2g\times{}12}}=\sqrt{\dfrac{4}{12}}=0.577$

ADD COMMENT SHARE EDIT