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A vertical lift of total mass 750 kg acquires an upward velocity of 3m/s over a distance of 4m moving with constant acceleration starting from rest. Calculate the tension in the cable.
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Given:

m=750kg

u=0m/s

v=3m/s

S=4m

a=constant

v2=u2+2aS

(3)2=0+2×a×(4)

a=1.125 m/s2 

Applying D’Alemberts Principle -

Fy=0

Tmamg=0

T=m(a+g)

=750×(1.125+9.81)

T=8201.25 N

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