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A force of 1200N acts along PQ, P(4,5,-2) and Q(-3,1,6)m. calculate its moment about a point A(3,2,0)m
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Fpq=1200NΔx=34=7Δy=15=4Δz=6(2)=8S=Δx2+Δy2+Δz2=11.36l=ΔxS=0.62;m=ΔyS=0.35;n=ΔzS=0.7Fx=744N;Fy=420N;Fz=840NˉrAP=(43)i+(52)j+(20)k=i+3j2kMA=ˉFˉr

MA=|ijk744420840132|

MA=i(420(2)840×3)j(744(2)840)+k(744×3420)MA=3360i+2328j+1812kNm

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