0
704views
Find centroid of shaded area.
1 Answer
written 3.5 years ago by |
Sr. No. | Part | Area | X coordindate of C.G (x1) | Y coordinate of C.G (y1) | Ax1 | Ay1 |
---|---|---|---|---|---|---|
1 | Rectangle l=200, b=100 | $A=l\times b =200 \times100=20000$ | $\dfrac{l}{2} = \dfrac{200}{2}= 100$ | $\dfrac {b}{2} = \dfrac{100}{2} = 50$ | $20000 \times 100$= 2000000 | $20000 \times 50$ = 1000000 |
2 | Triangle b=60, h=50 | $0.5\times b\times h$ | ||||
$0.5\times 60 \times 50$= 1500 | $2\times \dfrac{b}{3}$= $2 \times 60 /3$ = 40 | $100+\dfrac{h}{3} = 100+\dfrac{50}{3}$ | ||||
=116.67 | $1500 \times 40$ = 60000 | $1500 \times 116.67$= 175005 | ||||
3 | Semicircle radius (r)=50 | $-0.5\times\pi\times r^2$ |