0
2.8kviews
A cylinder of weight 500N is kept on two inclined planes as shown in the figure. Determine the reactions at the contact points A & B.
1 Answer
2
214views

Let C be the centre and A, B be the contact points.

Reaction forces RA,RB and weight Ware under equilibriumat centre point C.

Hence,RAsin(18030)=RBsin(18050)=500sin(30+50)

Hence,RAsin(150)=RBsin(130)=500sin(80)

RA=500sin(150)sin(80)

=253.8567 N

RB=500sin(130)sin(80)

=388.9310 N

Hence, the reaction at contact point A =RA=253.8567 N with 50and the reaction at contact point B =RB=388.9310 N with 30

Please log in to add an answer.