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A ladder of 4 m length weighing 200N is placed as shown in fig. 13 ?b=0.25 & ?A=0.35. Calculate the minimum horizontal force to be applied at A to prevent slipping.
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MA=0

200(2cos600)+0.25RB(4cos600)600(3cos600)+0.25RB(4sin600)=0

Rb=277.49N

Fy=0

..RA200600+0.25RB=0

RA=277.49N

Fx=P+0.35RARB=0

P+0.35(730.63)277.49=0

..P=21.77N

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