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A force F =80i +50j-60k passes through a point A(6,2,6). Compute its moment about point B(8,1,4).
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We are asked to find the Moment about a point in 3-D. And we already know that:

Moment (M) = distancr(r) x Force(F)   


Bold letters represent vector quantities here and 'X' signifies cross product.


Now we are provided with F and two points in space. So to find moment about B. We first find r:

rAB= (6i + 2j + 2k) - (8i + 1j + 4k)

  = -2i + j + 2k

So MrF = (-2i + j + 2k) x (80i + 50j- 60k)

                    = (-40i + 280j - 180k)

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