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A force F =80i +50j-60k passes through a point A(6,2,6). Compute its moment about point B(8,1,4).
1 Answer
written 3.5 years ago by |
We are asked to find the Moment about a point in 3-D. And we already know that:
Moment (M) = distancr(r) x Force(F)
Bold letters represent vector quantities here and 'X' signifies cross product.
Now we are provided with F and two points in space. So to find moment about B. We first find r:
r= AB= (6i + 2j + 2k) - (8i + 1j + 4k)
= -2i + j + 2k
So M= rx F = (-2i + j + 2k) x (80i + 50j- 60k)
= (-40i + 280j - 180k)