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Locate the centroid of the shaded portion w.r.t to ox & oy axes (fig 7).
1 Answer
written 3.9 years ago by |
The centroid always lies on the axis of symmetry ¯x=120mm
To find ¯y:
A1=Area of rectangle=120×240=28800 mm2
y1=(1202)=60mm
A2=Area of semicircle=π(90)22=−1272304mm2
y2=120−4(90)3π=81.8mm
¯y=A1y1+A2y2A1+A2=28800×60−112723.4×81.828800−12723.4=42.747mm