0
2.0kviews
A particle travels on a circular path, whose distance travelled is defined by S=(0.5t3+3t)m. If the total acceleration is 10 m/s2, at t=2 sec, find its radius of curvature.
1 Answer
0
364views

To answer this question we should know following key points:

1. Total Acceleration is given as atotal=(at)2+(an)2

2. at=dvdt and an=v2ρ

Here, s=0.5t3+3t m 

v=dsdt=1.5t2+3 m/s

and 

at=dvdt=3t m/s2 Hence, at t = 2 sec, $v=1.52^2+2=9 \text{ m/s }anda_t=32=6 …

Create a free account to keep reading this post.

and 2 others joined a min ago.

Please log in to add an answer.