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For a vehicle moving along a straight line, v-t diagram is as shown in figure below. Plt a-t & s-t diagrams for the given time period.

written 3.5 years ago by teamques10 ★ 68k

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engineering physics

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written 3.5 years ago by teamques10 ★ 68k

Acceleration = Slope of v - t graph

$\therefore \ For\ 0\lt t\ \lt 5\ sec, \ \ \ a=\dfrac{5-5}{5-0}=0\\ \therefore \ For \ 5\lt t\ \lt 15\ sec, \ \ \ a=\dfrac{20-5}{15-5}=1.5\ m/s^2$

$S_0=0\\ \therefore S_5=S_0+(5\times 5)=25\\ \therefore S_{15}=S_5+\Bigg[(10\times 5)+\dfrac{1}{2}(10\times 15)\Bigg]=150\ m$

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