Find Centroid of shaded area with reference to X and Y axes.

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written 3.9 years ago by

teamques10 ★ 69k

modified 3.1 years ago by

pedsangini276 • 4.8k

engineering mechanics

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written 3.9 years ago by

teamques10 ★ 69k

Part	$A_i \ \ \ (cm^2)$	$x_i\ \ \ (cm)$	$y_i \ \ \ (cm)$	$A_ix_i\ \ (cm^3)$	$A_iy_i\ \ (cm^3)$
Square ABCD	$20\times 20=400\ \ cm^2$	$=\dfrac{20}{2}=10\ cm$	$=\dfrac{20}{2}=10\ cm$	4000	4000
Quarter Circle	$-100\pi$	$\dfrac{4\times R}{3\pi }=\dfrac{4\times20}{3\pi }=8.488cm$	$R-\dfrac{4\times R}{3\pi }=20-\dfrac{4\times 20}{3\pi }=11.512 \ cm$	-2666.58	-3616.60 …

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