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In a balanced three phase circuit, power is measured by two wattmeters, the ratio of two wattmeter readings is 2:1. Determine the power factor of the system.
written 3.9 years ago by gravatar for teamques10 teamques10 ★ 69k modified 3.4 years ago by gravatar for pedsangini276 pedsangini276 • 4.8k
basic electrical engineering
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written 3.9 years ago by gravatar for teamques10 teamques10 ★ 69k

Given:

W1W2=21   i.eW1=2W2

To find: Power factor

ϕ=tan−1[√3(W1−W2)W1+W2]=tan−1[√3(W1−W2)W1+W2]=tan−1√3W23W2ϕ=tan−1(0.557)=30∘Power factor=cosϕ=cos30∘=0.8661

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