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A voltage of 150V, 50Hz is applied to a coil of negligible resistance and inductance 0.2H. Write the time equation for voltage and current.
1 Answer
written 3.5 years ago by |
Given:
Coil resistance = 0 (approx)
L= 0.2H; VS = 150 V; f= 50Hz
To Find: i(t), v(t)
Step 1: Time equation for voltage
$X_L=2π\times50\times0.2=62.83 \ Ω \\[2ex] V_{rms}=150 \ V \\[2ex] ∴v(t)=V_m sinωt=212.13 \ sin(100πt) \ Volt $
Step 2: Time equation for current
Peak current
$I_m=\dfrac{V_m}{X_L} =\dfrac{212.13}{62.83}=3.83 \ Amp$
Due to purely inductive voltage, the current will lag behind voltage by 90° or by (π/2) radians.
$i(t)=3.38 sin \displaystyle{(100πt-\dfrac{π}2)} Amp$