With proper phase diagrams, explain behaviour of a pure capacitor ina AC circuit.

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written 3.9 years ago by

teamques10 ★ 69k

• modified 3.9 years ago

engineering physics

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written 3.9 years ago by

teamques10 ★ 69k

(1) $Z=R+(X_L-X_C)j =-jX_C = X_C\angle -90$

(2) $I=\dfrac{V}{Z}=\dfrac{V\angle 0}{X_C\angle -90}=\left ( \dfrac{V}{X_C} \right )\angle 0 -(-90)\\[2ex] I=I_C\angle 90$

(3) In a pure capacitive circuit, current leads the voltage by $90^\circ$

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