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Find the value of circuit elements and reactive voltampere drawn for a balanced 3 phase load connected in delta and draws a power 12k W at 440V. The power factor is 0.7 leading.
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Given

Delta Connection

P = 12000W

VL=440V

P.f = 0.7(lead)

Find:

R = ?

X = ?

Q = ?

Formulae

VL=VphIL=3IphP=3VL IL cosϕp.f=cosϕ

Solution

P=3VLIL Cosϕ12000=440×IL×0.7IL=39AIph=IL/3=22.5AZph=VphIph=44022.5=19.5Ω

from Impendence triangle ,

ϕ=cos1 0.7=45R=Zcosϕ=19.5×0.9=13.65ΩX=Zsinϕ=19.5×sin45=12.66Ω

From Power triangle

tanϕ=QP⇒=P tanϕ=12tanϕ=12tan45=12KVA

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