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An alternating current takes 3.375 ms to reach 15A for the first time after becoming instantaneously zero. The Frequency of the current is 40 Hz. Find the Maximum value of the alternating current.

written 3.6 years ago by teamques10 ★ 68k

modified 2.8 years ago by pedsangini276 • 4.8k

engineering mechanics

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1 Answer

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written 3.6 years ago by teamques10 ★ 68k

Given:

t = 3.375 ms = 0.003375

T = $\dfrac{1}{f}$ = 0.025 s

i = 15A

Formula:

$i=i_m \sin wt\\ w=\dfrac{2\pi}{T}$

Solution:

$15=i_m \sin \left (\dfrac{2\pi \times 3.375\times10^{-3}}{0.025}\right)\\ \therefore i_m = 1013.24 A$

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