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An alternating current takes 3.375 ms to reach 15A for the first time after becoming instantaneously zero. The Frequency of the current is 40 Hz. Find the Maximum value of the alternating current.
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Given:

t = 3.375 ms = 0.003375

T = $\dfrac{1}{f}$ = 0.025 s

i = 15A

Formula:

$i=i_m \sin wt\\ w=\dfrac{2\pi}{T}$

Solution:

$15=i_m \sin \left (\dfrac{2\pi \times 3.375\times10^{-3}}{0.025}\right)\\ \therefore i_m = 1013.24 A$

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