0
8.1kviews
State and explain maximum power transfer theorem.
1 Answer
2
876views
written 3.5 years ago by |
Maximum Power Transfer Theorem for DC circuits:-
Maximum Power Transfer Theorem states that in a active DC network, the maximum power will be transferred from source to the load when the external load resistance equals to the internal resistance of the source.
Consider any circuit which is replaced by Thevenin’s voltage source in series with Thevenin’s equivalent resistance connected across the complex load RL.
- The current through the above circuit is given as,
$I = \dfrac{V_{TH}}{R_{TH}+R_L}$
- Power delivered to the load is given by
$P_L = I^2R_L$
- Subtituting current I in the above equation we have
$P_L = \dfrac{V^2_{TH}\times R_L}{(R_{TH}+R_L)^2}$
- To find the value of RL at which maximum power is delivered to the load then differentiate PL with respect to RL and equates it to zero.
$\dfrac{dP_L}{dR_L} = \dfrac{d}{dR_L}\left[ \dfrac{V^2_{TH}\times R_L}{(R_L+R_{TH})^2}\right]=0$
- Then we get
$\ \ \ \ \ \ \ R_L+R_{TH}=2R_{L} \\ \Rightarrow R_L=R_{TH}$
- Therefore, in DC circuits, if RL = RTH, maximum power transfer takes place from source to load. This implies that maximum power transfer occurs when the resistance of the load is equal to the thevenin's resistance , i.e., RL = RTH
- When RL = RTH then maximum power is given by
$P_{MAX} = \dfrac{V^2_{TH}}{4R_{TH}} = \dfrac{V^2_{TH}}{4R_{L}}$
ADD COMMENT
EDIT
Please log in to add an answer.