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Draw and explain the phasor diagram of 1−ϕ
1 Answer
written 3.9 years ago by |
The magnetising componentIμ is responsible for setting up fluxes in the core. It is in phase with the fluxϕ.
Iμ=Io sin ϕo
The active component Iw is responsible for power loss in the transformer. It is in phase with V1.
Iw=Io cosϕo
Hence, no load current Io is the phaser sum ofIμ and Iw.
Io=Iμ+IwIo=√I2μ+I2w
The no load current Io is very small as compared to full load current I1. Hence copper loass is negligible and no load input power is practically equal to iron loss or core loss in the transformer.
Phasor Diagram: The phasor diagram is shown in Fig. 1.
Fig. 1 Phasor Diagram