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Find the interplaner spacing between the family of planes (111) in a crystal of lattice constant 3A?.
1 Answer
written 3.9 years ago by |
Given –
a=3A∘=3×10−10
h=1,k=1,l=1
To find – d Solution – d=a√h2+k2+l2 =3×10−10√(1)2+(1)2+(1)2 =3×10−10√3 d=1.73×10−10 ∴ Interplanar Spacing is 1.73A∘