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Calculate the critical radius ratio of an ionic crystal in ligancy 4 configuration.
1 Answer
written 3.5 years ago by |
Ligancy:
Fig. 1 Determination of the size of the tetrahedral void
$\therefore \dfrac{AO}{AJ}=\dfrac{AG}{AE}$
$AO=r_a+r_c\\ AJ=r_a\\ AE=\sqrt{2}a\\ AG=\sqrt {3}a$
$\therefore \ \dfrac{AO}{AJ}=\dfrac{AG}{AE}=\dfrac{r_a+r_c}{r_a}=\dfrac{\sqrt{3}a}{\sqrt{2}a}$
$\therefore \ 1+\dfrac{r_c}{r_a}=\dfrac{\sqrt{3}}{\sqrt{2}}$
$\therefore \ \ \dfrac{r_c}{r_a}=\dfrac{\sqrt3-\sqrt 2}{\sqrt 2}=0.225$