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Calculate Bragg angle if (200) planes of a BCC crystal with lattice parameter 2.814Å give second order reflection with X-rays of wavelength 0.71Å.
1 Answer
written 3.9 years ago by |
For plane (200):
d=a√h2+k2+l2
d=2.814×10−10√22+0+0
∴d=2.814×10−102
∴d=1.407×10−10 m
Using Bragg's law
nλ=2dsinθ
sinθ=nλ2d
sinθ=2×0.71×10−102×1.407×10−10
sinθ=0.5046
θ=sin−10.5046
∴θ=30.31∘
∴ Bragg's angle is 30.30°