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Fermi Energy for Silver is 5.5 eV. Find out the energy for which the probability of occupancy at 300K is 0.9.
1 Answer
written 3.9 years ago by |
Given data:
f(E)=0.9
To find: E = ?
Solution:
kT=1.38×10−23×3001.6×10−19
∴kT=0.0259
f(E)=11+e(E−Ef)kT
0.9=11+e(E−5.5)0.0259
1+e(E−5.5)0.0259=10.9
1+e(E−5.5)0.0259=1.1111
∴e(E−5.5)0.0259=1.1111−1
∴e(E−5.5)0.0259=0.1111
Taking log on both sides,
$\log {e^{(E-5.5)\over …