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Calculate the electronic polarizability of A1. Given number of Air atoms at NTP=2.7×1025/m3 and dielectric constant of Ar=1.0024.
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written 3.5 years ago by
teamques10
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- We know that the electronic polarizability$\mathrm{a_e}$ is
$\mathrm{a_e = \dfrac{\varepsilon_0(\varepsilon_r-1)}{N}}$
- Substituting the values, we get
$\mathrm{=\dfrac{8.85 \times 10^{-12} \times (1.0024 -1)}{2.7 \times 10^{25}}}$
$\mathrm{= 7.866 \times 10^{-40} F m^2}$
- Therefore, the electonic polarisability of air atom at NTP is equal to$\mathrm{7.866 \times 10^{-40} F m^2}$
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