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What is the probability of an electron being thermally promoted to conduction band in diamond at 27°C, if bandgap is 5.6 eV wide.
1 Answer
written 3.9 years ago by |
f(Ec) = 1 1+e(Ec−EvRT)
K = Boltzman constant = 1.38 ×10-23 J/K
In eV it is given by
K(in eV) = 1.38×10−231.6×10−6 = 86.25 × 10-6 eV
Also in intrinsic semiconductor
EC - EV = Eg2
Ec - Ev = 5.62 = 2.8
Ec−Ev KT = 2.886.25×10−6×(27+273) = 108.212
f(Ec) = 11+e108.212
f(EC) = 1×10−47
It implies that it is insulator.