Here,  $E_F-E=0.012eV$

$kT=\dfrac{1.38\times 10^{-23}\times 300}{1.6\times 10^{-19}}=0.02587\ eV$

$\therefore \ \ The \ probability\ of\ an\ energy\ level\ not\ being\ occupied\ by\ an \ electron\ is \ 1-f(E).$

$1-f(E)=1-\dfrac{1}{1+exp(E-E_F)/kT}\\ 1-f(E)=1-\dfrac{1}{1+exp\Bigg(\dfrac{0.012}{0.02587}\Bigg)}=0.614$