In a solid, consider the energy level lying 0.012ev below Fermi level. What is the probability of this level not being occupied by an electron? Given T=300 Kelvin. Ks=1.38×10-23 j/K.

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teamques10 ★ 66k

• modified 3.3 years ago

engineering physics

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written 3.3 years ago by

teamques10 ★ 66k

Here, $E_F-E=0.012eV$

$kT=\dfrac{1.38\times 10^{-23}\times 300}{1.6\times 10^{-19}}=0.02587\ eV$

$\therefore \ \ The \ probability\ of\ an\ energy\ level\ not\ being\ occupied\ by\ an \ electron\ is \ 1-f(E).$

$1-f(E)=1-\dfrac{1}{1+exp(E-E_F)/kT}\\ 1-f(E)=1-\dfrac{1}{1+exp\Bigg(\dfrac{0.012}{0.02587}\Bigg)}=0.614$

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