A class room has dimensions 20 × 15 × 5 m3. The reverberation time is 3.5 sec. Calculate the total absorption of its surface and average absorption coefficient.

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written 3.6 years ago by

teamques10 ★ 68k

• modified 3.6 years ago

control systems

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written 3.6 years ago by

teamques10 ★ 68k

(Given) T = 3.5 sec

V = 20 x 15 x 5 = 1500 $m^3$

S = $2 [ 20 \times 15+15\times5+20\times5]= 950 m^2. $

T = $\dfrac {0.161V }{aS}$

Hence, Average absorption, a = $\dfrac {0.161\times 1500 }{3.5 \times 950} = 0.0.72$

Total Absorption of surface = $a \times S$

= 0.072 x 950 = 68.4 $m^2S$

Total Absoption = 68.4 $m^2S$

Average absorption = 0.072

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