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Solve the equation 7coshx+8sinhx = 1 for real values of x.
written 3.9 years ago by |
7coshx+8sinhx = 1
7(ex+e−x2)+8(ex−e−x2)=1
7ex+7e−x+8ex−8e−x=2
15ex−e−x=2
multiplying the above equation by ex we get
15e2x−1=2ex
15e2x−2ex=1
ex=13,−15
x=log(13)=−log(3)