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Calculate all types of hardness of water sample containing: Ca(HCO3)2=81 ppm MgSO4=60 ppm, MgCO3=42 ppm, Ca(NO3)2=82 ppm.

written 3.6 years ago by teamques10 ★ 68k

modified 3.1 years ago by pedsangini276 • 4.8k

engineering chemistry

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written 3.6 years ago by teamques10 ★ 68k

CONSTITUENTS	QUANTITY IN ppm	MULTIPLICATION FACTOR	CaCO3 EQUIVALENT
Ca(HCO3)2	81	$\dfrac{100}{162}$	$\dfrac{81 \times 100}{162}=50$
MgSO4	60	$\dfrac{100}{120}$	$\dfrac{60 \times 100}{120}=50$
MgCO3	42	$\dfrac{100}{84}$	$\dfrac{42 \times 100}{84}=50$
Ca(NO3)2	82	$\dfrac{100}{164}$	$\dfrac{82 \times 100}{164}=50$

 

Temporary hardness = Hardness caused due to[Ca(HCO3)2 + MgCO3] $= 50 + 50 =100 \ \mathrm {ppm}$

Permanent hardness = Hardness caused due to[MgSO4 + Ca(NO3)2 $= 50 + 50 =100 \ \mathrm {ppm}$

Total hardness = Temporary hardness + Permanent hardness $=100 + 100 =200\ \mathrm {ppm}$

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