Given:

Volume of oil=5ml,

Volume of KOH=2ml,

Density of oil=0.92,

Normality of KOH=0.01N.

To find: Acid value

To find the weight of oil,

$density=\dfrac{mass}{volume}$  or $mass=density\times volume$

weight of the oil=0.92$\times$5

                          =4.60

$Acid $ $value $=$\dfrac{volume of KOH\times normality of KOH\times56}{weight of oil} $

Hence acid value=$\dfrac{2\times0.01\times56}{4.60}$

 acid value=0.243 mg of KOH