University Name > First Year Engineering > Semester > Physical Chemistry

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$H_2O_2 + 2KI \to 2KOH +I_2$ $\\ $

${ I_2 + 2Na_2S_2O_3 \to Na_2S_4O_6 + 2NaI }\\ $

$20$ ml of ${ 0.3(N) Na_2S_2O_3 = 20 × 0.3 × 10^{ –3 } } \\$ $= 6 × 10^{ –3 }$ moles moles of ${ H_2O_2 }$ present $= 3 × 10^{ –3 }$ mol. molarity of ${ H_2O_2 }$ solution = $\dfrac { 3\times 10^{ -3 }}{ 25 }\times 10^3$ $=\dfrac 3{ 25 }( M )$ the vol strength of ${ H_2O_2 }$ solution $=\dfrac 3{ 25 }× 11.2 = 1.344$ vol